Class 10 Math Chapter 11 Areas Related to Circles Solutions

Here, Class 10 Math Chapter 11 Areas Related to Circles Solutions are provided. Subject matter experts have created these solutions to help students in their board exam. They have created solutions in such a way that students can revise the entire solutions in very little time and can score good marks in the board exam. Every solution is provided in detail and in very simple language.

Class 10 Math Chapter 11 Areas Related to Circles Solutions are very important for board exam. Solving these Areas Related to Circles solutions will boost the confidence and students can score better in exam. Solutions are provided according to latest NCERT syllabus. Experts created these step-by-step solutions, which will definitely be helpful for students.

Areas Related to Circles Solutions

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Chapter 10: Circles Solutions
Chapter 12: Surface Areas and Volumes Solutions

We have given solutions of all exercise of class 10 math chapter 11. These solutions will be helpful for students understanding core concept of Triangles.

To understand the chapter thoroughly, it is essential to practice all the questions provided within it, as well as any additional questions. Solving previous years’ question papers also proves to be very helpful in exam preparation. You can also find other study material resources on our website.

Important Questions for NCERT Chapter 11: Areas Related to Circles

Question :Find the area of a sector of a circle with radius 6cm if angle of the sector is 60°

[Use π=227].\left[ \text{Use } \pi = \frac{22}{7} \right].

Answer :

Let OACB be a sector of the circle making 60∘ angle at centre O of the circle.Area of sector of angle θ=θ360∘×πr2Area of sector OACB =60∘360∘×227×(6)2\begin{array}{l} \text{Let OACB be a sector of the circle making } 60^\circ \text{ angle at centre O of the circle.} \\ \text{Area of sector of angle } \theta = \frac{\theta}{360^\circ} \times \pi r^2 \\ \text{Area of sector OACB } = \frac{60^\circ}{360^\circ} \times \frac{22}{7} \times (6)^2 \end{array}
=16×227×6×6=1327 cm2Therefore, the area of the sector of the circle making 60∘ at the centre of the circle is132/7 cm2.\begin{array}{l} = \frac{1}{6} \times \frac{22}{7} \times 6 \times 6 = \frac{132}{7} \text{ cm}^2 \\ \\ \text{Therefore, the area of the sector of the circle making } 60^\circ \text{ at the centre of the circle is} \\ 132/7 \text{ cm}^2. \end{array}

Question :An umbrella has 8 ribs which are equally spaced (see figure). Assuming umbrella to be a flat circle of radius 45cm, find the area between the two consecutive ribs of the umbrella.

[Use π=227].\left[ \text{Use } \pi = \frac{22}{7} \right].

Answer :

There are 8 ribs in an umbrella. The area between two consecutive ribs is subtending

360∘8=45∘ at the centre of the assumed flat circle.\frac{360^\circ}{8} = 45^\circ \text{ at the centre of the assumed flat circle.}
Area between two consecutive ribs of circle =45∘360∘×πr2=18×227×(45)2=1128×2025=2227528 cm2\begin{array}{l} \text{Area between two consecutive ribs of circle } = \\ \frac{45^\circ}{360^\circ} \times \pi r^2 \\[2ex] = \frac{1}{8} \times \frac{22}{7} \times (45)^2 \\[2ex] = \frac{11}{28} \times 2025 = \frac{22275}{28} \text{ cm}^2 \end{array}

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